Circuit Analysis II
Intermediate level electrical engineering textThen, since in general adB = 20logb, and that y = logx implies x = j(r , we have HP 14 m 10 = 0.25 and therefore 1f we wish to ... we get g5000=0.01 1 *5000j/((1 +50j}* fprintf(a#39;\na#39;); fprintf(a#39;mag = %6.2f \ta#39;, abs(g5000));... fprintf(a#39;phase = %6.2f deg.
| Title | : | Circuit Analysis II |
| Author | : | Steven T. Karris |
| Publisher | : | Orchard Publications - 2003 |
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